langchain.smith.evaluation.runner_utils
.TestResult¶
- class langchain.smith.evaluation.runner_utils.TestResult[source]¶
一个单次测试运行结果的字典。
Methods
__init__
(*args, **kwargs)clear
()copy
()fromkeys
([value])Create a new dictionary with keys from iterable and values set to value.
get
(key[, default])Return the value for key if key is in the dictionary, else default.
返回反馈分数的分位数。
items
()keys
()pop
(k[,d])If the key is not found, return the default if given; otherwise, raise a KeyError.
popitem
()Remove and return a (key, value) pair as a 2-tuple.
setdefault
(key[, default])Insert key with a value of default if key is not in the dictionary.
将结果转换为数据框。
update
([E, ]**F)If E is present and has a .keys() method, then does: for k in E: D[k] = E[k] If E is present and lacks a .keys() method, then does: for k, v in E: D[k] = v In either case, this is followed by: for k in F: D[k] = F[k]
values
()- __init__(*args, **kwargs)¶
- clear() None. Remove all items from D. ¶
- copy() a shallow copy of D ¶
- fromkeys(value=None, /)¶
Create a new dictionary with keys from iterable and values set to value.
- get(key, default=None, /)¶
Return the value for key if key is in the dictionary, else default.
- get_aggregate_feedback() pd.DataFrame [source]¶
返回反馈分数的分位数。
该方法计算并打印所有反馈键上的反馈分数的分位数。
- 返回:
包含每个反馈键的分位数的DataFrame。
- Return type
pd.DataFrame
- items() a set-like object providing a view on D's items ¶
- keys() a set-like object providing a view on D's keys ¶
- pop(k[, d]) v, remove specified key and return the corresponding value. ¶
If the key is not found, return the default if given; otherwise, raise a KeyError.
- popitem()¶
Remove and return a (key, value) pair as a 2-tuple.
Pairs are returned in LIFO (last-in, first-out) order. Raises KeyError if the dict is empty.
- setdefault(key, default=None, /)¶
Insert key with a value of default if key is not in the dictionary.
Return the value for key if key is in the dictionary, else default.
- update([E, ]**F) None. Update D from dict/iterable E and F. ¶
If E is present and has a .keys() method, then does: for k in E: D[k] = E[k] If E is present and lacks a .keys() method, then does: for k, v in E: D[k] = v In either case, this is followed by: for k in F: D[k] = F[k]
- values() an object providing a view on D's values ¶