numpy.dtype.byteorder

属性

dtype.byteorder

指示此数据类型对象的字节顺序的字符.

One of:

‘=’	native
<	little-endian
‘>’	大端序
‘|’	不适用

所有内置的数据类型对象的字节顺序要么是 ‘=’ 要么是 ‘|’.

示例

>>> import numpy as np
>>> dt = np.dtype('i2')
>>> dt.byteorder
'='
>>> # endian is not relevant for 8 bit numbers
>>> np.dtype('i1').byteorder
'|'
>>> # or ASCII strings
>>> np.dtype('S2').byteorder
'|'
>>> # Even if specific code is given, and it is native
>>> # '=' is the byteorder
>>> import sys
>>> sys_is_le = sys.byteorder == 'little'
>>> native_code = '<' if sys_is_le else '>'
>>> swapped_code = '>' if sys_is_le else '<'
>>> dt = np.dtype(native_code + 'i2')
>>> dt.byteorder
'='
>>> # Swapped code shows up as itself
>>> dt = np.dtype(swapped_code + 'i2')
>>> dt.byteorder == swapped_code
True